Question:
a road whose width is 7m surrounds a circular path whose circumference is 352m. find the area of the road.
Answer:
Let radius of the circular track is r
Given, circumference of the circular track = 352
=> 2πr = 352
=> πr = 352/2
=> πr = 176
=> (22/7) * r = 176
=> 22r/7 = 176
=> r/7 = 176/22
=> r/7 = 8
=> r = 7*8
=> r = 56
Now, radius of the circular track including road R = 56 + 7 = 63
So, area of the road = π(R2 - r2 )
=> area of the road = π(632 - 562 )
=> area of the road = π(63 - 56)*(63 + 56) {since (a2 - b2 ) = (a - b)*(a + b) }
=> area of the road = (22/7)*7*119
=> area of the road = 22*119
=> area of the road = 2618 m2
Not what you are looking for? Go ahead and submit the question, we will get back to you.
