Question:
an elevator descends into a mine shaft at the rate of 6m/min if the descents starts from 10 m above the ground level how long will it take to reach -350m
Answer:
Given, an elevator descends into a mine shaft at the rate of 6m/min.
Now, the total distance mine shaft have to travel = -350 - 10 = - 360 m {Negative sign represents it gows dowm}
So, time taken = 360/6 = 60 minutes
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