Question:
A boy goes to school at a speed of 8 km/h and return to home at a speed of 6 km/h. If he taked 3 hours and 30 minutes in all then find the distance between them?
Answer:
Given, A boy goes to school at a speed of 8 km/h and return to home at a speed of 6 km/h.
He taked 3 hours and 30 minutes in all.
Let S1 = 8, S2 = 6
and T = 3 hours and 30 minutes
= (3 + 30/60) hours
= (3 + 1/2) hours
= (6 + 1)/2 hours
= 7/2 hours
Now, the distance between the school and the home = T * {(S1 * S2 )/(S1 + S2 )}
= (7/2) * {(8 * 6)/(8 + 6)}
= (7/2) * (48/14)
= (7 * 48)/(2 * 14)
= 48/(2 * 2)
= 48/4
= 12 km
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