Question:
A small telescope has an objective lens of focal length 144cm and an eyepiece of focal length 6.0cm. What is the magnifying power of the telescope? What is the separation between the objective and the eyepiece?
Answer:
Focal length of the objective lense (f0) = 144 cm
Focal length of the eyepiece (fe) = 6 cm
The magnifying power of the telescope (m) = f0/ fe = 144/6 = 24 cm
The separation between the objective lens and the eyepiece is = 144 + 6 = 150 cm
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