Question:
A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil?
Answer:
Number of turns on the circular coil, n = 100
Radius of each turn, r = 8.0 cm = 0.08 m
Current flowing in the coil, I = 0.4 A
Magnitude of the magnetic field at the centre of the coil is given by the relation,
| B | = 
Where,
= Permeability of free space
= 4π × 10–7 T m A–1
| B |=
Hence, the magnitude of the magnetic field is 3.14 × 10–4 T.
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