The magnetic field on the axis of the magnet at a distance d1= 14 cm, can be written as:

  …(i)

Where,

M = Magnetic moment

= Permeability of free space

H= Horizontal component of the magnetic field at

If the bar magnet is turned through 180°, then the neutral point will lie on the equatorial line.

Hence, the magnetic field at a distance , on the equatorial line of the magnet can be written as:

…(2)

Equating equations (1) and (2), we get:

s

The new null points will be located 11.1 cm on the normal bisector.