Question:
A long straight horizontal cable carries a current of 2.5 A in the direction 10degree south of west to 10degree north of east. The magnetic meridian of the place happens to be 10degree west of the geographic meridian. The earths magnetic field at the location is 0.33 G, and the angle of dip is zero. Locate the line of neutral points (ignore the thickness of the cable). (At neutral points, magnetic field due to a current-carrying cable is equal and opposite to the horizontal component of earths magnetic field.)
Answer:
Current in the wire, I= 2.5 A
Angle of dip at the given location on earth, 
= 0°
Earth’s magnetic field, H= 0.33 G =
The horizontal component of earth’s magnetic field is given as:
= H cos
The magnetic field at the neutral point at a distance Rfrom the cable is given by the relation:
Where,
= Permeability of free space = 
Hence, a set of neutral points parallel to and above the cable are located at a normal distance of 1.51 cm.
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