Question:
state and explain kirchoff's second law of electricity
Answer:
Kirchoff second Law:
Kirchoffs second law states that in a closed loop, algebraic sum of Emfs is equal to the algebraic sum of product of resistances and respective currents flowing through them.
Explanation:
We need to find a closed circuit and apply the sign conventions correctly.
In the above diagram, we are applying +ve value of emf if the current leaves the positive terminal of the battery. Similarly the direction of I determines the direction of IR.
Applying Kirchoffs second law, we find –V2 + V1 = IR1 + IR2 + IR3
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