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Question:
mam in the video part 16 of this chapter you explained the proof of "elecric field intensity due to point charge" but i didn't get that in the final step how the fraction of each component of field became (x^2+y^2+z^2)^3/2... i hope mam you get my doubt..plz help me
Answer:

There is a test charge q0 , and  vector r is its position vector.

vector r =xi +yj +zk

As we know that a vector quantity have both magnitude and direction.

The unit vector shows the direction of a vector and the magnitude we get as-

r = √(x2 +y2 +z2)  = (x2 +y2 +z2)1/2

Now, E = (kq/r2) r^  ......(1)

Here, r^ is the unit vector, and we can write it as-

r^ = vector r/ r .....(2)

Now if we put the value of r^ in equation (1), we get-

E = (kq/r3) vector r

and the value of r =(x2 +y2 +z2)1/2

Hence, E= (kq/(x2 +y2 +z2)3/2) vector r

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