learnohub
Question:
find the force in free space between two like point charge of one coulomb each placed 1m apart
Answer:

According to couloumb law

F = k [q1q2] / r2 where k = 1/4π€0 (€0 = 8.854 * 10-12 C2N-1m-2 nis called permittivity of free space)

As the charges are like charges, they will repel each other.

Also,  given q = 1couloumb and   r=1 m

1/4π€0  = 9 * 109 N

F = 9×109  × (1.6×10−10)2 / 12

F=2.3×10−28N.

Not what you are looking for? Go ahead and submit the question, we will get back to you.

learnohub

Classes

  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • ICSE 6
  • ICSE 7
  • ICSE 8
  • ICSE 9
  • ICSE 10
  • NEET
  • JEE

YouTube Channels

  • LearnoHub Class 11,12
  • LearnoHub Class 9,10
  • LearnoHub Class 6,7,8
  • LearnoHub Kids

Overview

  • FAQs
  • Privacy Policy
  • Terms & Conditions
  • About Us
  • NGO School
  • Contribute
  • Jobs @ LearnoHub
  • Success Stories
© Learnohub 2026.