Question:
can u plz clear my concept hw can we find d values of electric field capacitance potential at different points
e.g if n drops of same size having same charge collapse to form a big drop how total charge on big drop ,potential of big drop, capacitance, electric field vary with respect to small drop nd why?
Answer:
r= radius of smaller drop
q= charge of smaller drop
v= potential of smaller drop
c = capacitance of smaller drop
R= radius of bigger drop
Q= charge of bigger drop
V= potential of bigger drop
C= capacitance of bigger drop
Total charge on the bigger drop= Sum of all the charge on small drops
Q = q1 + q2 + q3 etc
Q = Nq
Volume of N small drops= V = N x 4/3 πr³
Volume of the bigger drop = 4/3 πR³
so,
4/3 πR³ = N x 4/3 π r³
R = N¹/₃r
Potential on bigger drop = V = 1/ 4π Ɛo Q/R
= 1/4πƐ0 (Nq/N¹/₃r)
= N 2/3 * 1/ 4π Ɛo * q/r
V = N²/₃ * v
Capacitance of bigger drop C = 4πƐoR
Capacitance of smaller drop c = 4πƐor
C = 4πƐoN¹/₃r
C= N¹/₃(4πƐor)
C = N¹/₃c
Not what you are looking for? Go ahead and submit the question, we will get back to you.
