Question:
The wavelength of k alpha line in copper is 1.54 angstrom. The ionization energy of k electron in copper in joule is?
Answer:
Given wavelength = 1.54 * 10-10 m
Ionization energy of k electron = E = hc/λ = [ 6.625 * 10-34 * 3 * 108 ] / 1.54 * 10-10 = 4.62 * 10-16 J
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