Question:
Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).
Answer:
On the one hand, the quantum of energy of a photon is
E = h f
= h c/lambda
On the other hand, the relativistic energy for a massless particle is
E. = c p
This implies de Broglie relationship
p = h/lambda
where the de Broglie wavelength is the same lambda
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