

Given that if a machine is correctly set up, it produces 90% accepted items.
Now, P(A/E1 ) = probability that machine produces 2 acceptable items if it have correct setup = 90% * 90%
=> P(A/E1 ) = (90/100)*(90/100)
=> P(A/E1 ) = 0.9 * 0.9
=> P(A/E1 ) = 0.81
Since, machine produces 2 acceptable items,
So, 0.9 is multiplied two times.
Same for P(A/E2 ) = 0.4 * 0.4
Hope you got the point.
