Question:
a dice is tossed for 4 times so find the probablity for getting 1 for minimum 1times
Answer:
Let A is the event that 1 does not occur all the four time
So P(A) = (5/6)4
Now probability that occurs at least one time = 1- P(A )
= 1 - (5/6)4
= 1 - (625/1296)
= (1296-625)/1296
= 671/1296
So probability that occurs alteast one time is 671/1296
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