Question:
Bag I contains 3 red and 4 black balls and Bag II contains 4 red and 5 black balls. One ball is transferred from Bag I to Bag II and then a ball is drawn from Bag II. The ball so drawn is found to be red in colour. Find the Probability that the transferred ball is black.
Answer:
hello prabhakar here
the correct ans to this question is 11/20
P(B)=P(B/E1).P(E1)+P(B/E2).P(E2)
THIS IS THE SOLUTION JUST PUT
P(B/E1)=5/10 SINCE THE BALL WHICH IS TRANSFERRED CAN BE RED
P(B/E2)=6/10 SINE THE BALL CAN ALSO BE BLACK
P(E1)=1/2
P(E2)=1/2
BECAUSE THERE ARE ONLY TWO BAGS
THTS IT JUST SUBSTITUTE THE VLUES TO GET THE ANS
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