Question:
A pair of dice is thrown and the sum of the numbers appearing on the dice is observed to be 7.Find the probability that the number 5 has appeared on atleast one die.
Answer:
Here, n(S) = 36 ; two dice are trown
Let, A : Event of gettinf sum as 7;A = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}
B : Event that atleast one die has 5 ; B = {(2,5), (5,2)}
Thus P(B) = (2/36)/(6/36) = 2/6 = 1/3.
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