Question:
A pair of dice is rolled again and again till a total of 5 or a total of 7 is obtained . The chance that a total of 5 comes before a total of 7 is
Answer:
Favourable cases for 5: {(1,4), (2,3)}
Favourable cases for 7: {(1,6), (2,5), (3,4)}
Our sample space consist of only sum=5 compare to sum =7.
Therefore we can ignore all other cases.
Probability that 5 comes before 7 = {favourable cases(that is 5 comes)}/total cases
P = 2/(2+3)
P = 2/5
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