Question:
Integrate Log x
Answer:
∫ logx dx = logx∫ dx - ∫ {d(logx)/dx *∫ dx} dx
=> ∫ logx dx = logx * x - ∫ { 1/x * x} dx
=> ∫ logx dx = x*logx - ∫ dx
=> ∫ logx dx = x*logx - x + C
=> ∫ logx dx = x(logx - 1) + C
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