Question:
evaluate sin(2cos-1(-3/5))
Answer:
We know that
sin2x = 2*sinx*cosx
=> sin(2cos-1 (-3/5)) = 2*sin((cos-1 (-3/5)) * cos((cos-1 (-3/5))
= 2 *sin((sin-1 (4/5)) * cos((cos-1 (-3/5))
= 2*(4/5)*(-3/5) (since sin(sin-1 x) = x and cos(cos-1 x) = x)
= -24/25
So sin(2cos-1 (-3/5)) = -24/25
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