Question:
a solution containing 8.6g/l of urea is isotonic with 5% solution of unknown solute. The molar mass of the solute will be?
Answer:
Moles of urea = mass/ molar mass of urea = 8.6 g/60 g/mol = 8.6/60 mole
Concentration of urea solution = 8.6/60 mole/L
Moles of unknown solution = mass/ molar mass of unknown solution
5% of unknown solution = 5 g /100 ml = 50 g /1000 ml = 50/L
Moles of unknown solute = 50/m moles
Concentration of unknown solution = 50/m mole/L
Therefore,
8.6/60 mole/L = 50/m mole/L
m = 50 x 60/8.6 = 348.9 g/mole
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