Question:
If 0.62 gm of Na2CO3.H2O is added to 100 ml of 0.2 N HCl,What will be the nature of the resulting solution,acidic,basic or neutral and how
Answer:
The reaction taking place is as follows:
Na2CO3.H2O + H2SO4 à Na2SO4 + CO2 + 2H2O
W = (N x E x V) /1000
0.62 = (N x 62 x 100) /1000
N = (0.62 x 1000) /62 x 100
=0.1
Hence the resulting solution is acidic.
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