Question:
At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?
Answer:
Mass of glucose, w =36 g
Osmotic pressure, π = 4.98 bar
Temperature, T = 300 K
Volume of solution, V = 1L
Formula of osmotic pressure
π = CRT = n/VRT
R = π V/nT = 4.98 × 180/ (36 × 300) = 4.98/ 60 L atm K-1 mol– 1
π = CRT
C= π /RT
=1.52/4.98/60 x 300
=0.061 M
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