Question:
138 grams of ethyl alcohol is mixed with 72 grams of water. The ratio of mole fraction of alcohol to water is
Answer:
Ethyl alcohol = C2H5OH, Mol wt. = 46 g/mol
So, 46 g/mol = 1 mole
138 grams = 138/46 = 3 moles
Water = H2O, Mol wt = 18 g/mol
So, 18 g/mol = 1 mole
72 grams = 72/18 = 4 moles
Therefore, mole fraction of ethyl alcohol = No. of moles of ethyl alcohol/total no. of moles
= 3/(3+4) = 3/7
And, mole fraction of water = No. of moles of water/total no. of moles
= 4/(3+4) = 4/7
So, the ratio of mole fraction of alcohol to water = 3/7 ÷ 4/7
= 3:4.
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