Question:
100ml each of 0.5N NaOH,N/5 HCl and N/10 H2SO4 are mixed together.what will the resulting solution(acidic,neutral or alkaline)????and how to know it????
Answer:
100 mL of 0.5 N NaOH, = 0.100 L x 0.5 N = 0.05 equivalent moles
100 mL of N/5 HCL = 0.100 L x 0.2 N = 0.02 equivalent moles
100 mL of N/10 H2SO4 = 0.100 L x 0.1 N = 0.01 equivalent moles
0.02 equivalent moles of HCl will neutralise 0.02 equivalent moles of NaOH
And 0.01 equivalent moles of H2SO4 will neutralise 0.01 equivalent moles of NaOH
So unreacted equivalent moles of NaOH = 0.05 - (0.02 + 0.01) = 0.02
The resulting solution will be basic containing 0.02 equivalent moles of NaOH = 0.02 / 0.300 L = 0.067 N NaOH
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