Question:
How to write differential form of the rate expression in terms of partial pressure for
4NH3+5O2------4NO+6H2O
Answer:
Here the coeffi cients are 4, 5, 4, and 6.
So rate = -1/4 Δ[NH3]/ Δt = - 1/5 Δ[O2]/ Δt = 1/4 Δ[NO]/ Δt = 1/6 Δ[H2O]/ Δt
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