Question:
For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.
Answer:
Given,
Order of reaction = first
Let Initial amount = 100 g
Amount in % after 90 % completion = 100 - 90 = 10%
Amount in g [R]= 10% of 100g = 10g
Amount in % after 99 % completion = 100 - 99 = 1%
Amount in g [R]= 1% of 100g = 1g
Use the formula of first order reaction
We observe that t2 = 2t1
Hence, for a first order reaction, time required for 99% completion is twice the time required for the completion of 90% of reaction.
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