Question:
the bob of simple pendulum of length 1m is let to go when pendulum is inclined at an angle of 60 degree to the vertical find the velocity of the bob when it cross the position of rest
Answer:
Length of simple pendulum =1m
Mass =1wgm=0.1kg
It is displaced through as angle of 60 for vertical
Height of pendulum at starting position = length (1−ws60)
=1(1−0.5)
=0.5m
Potential energy =mgh=0.1×10×0.5=0.55
when it is released and it reaches mean position its potential energy at starting point is converted to kinetic energy.
so K.E. of bob at mean position =0.55.
Hence, the answer is 0.55.
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