Question:
The moment of inertia of a thin rod of mass M and length L about an axis passing through its centre and normal to its length is given by ML2/12. Using theorem of parallel axes, find its moment of inertia about an axis passing through on end and normal to its length, if L = 1m and M = 0.2 Kg
mam this question is from; motion of a rigid body
from nios [national institute of open schooling]
Answer:
The moment of inertia of a thin rod of mass M and length L about an axis passing through its centre and normal to its length is given by ML2/12. Using theorem of parallel axes, find its moment of inertia about an axis passing through on end and normal to its length, if L = 1m and M = 0.2 Kg mam this question is from; motion of a rigid body from nios [national institute of open schooling]
As given, the moment of inertia of a this rod about an axis passing through its centre and normal to its length is ML2 /12
This is shown in the diagram as axis AB
Now, we need Moment of inertia about an axis passing through its end and normal to its length as shown by the axis XY.
By parallel axis theorm, IXY = IAB + M(L/2)2
= ML2 / 12 + ML2 /4
= ML2/3
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