Question:
If a ball strikes elastically normal to a wall wid velocity v if the time of impact is dt then magnitude of impulsive force is?
Answer:
Impulsive force = Impulse /Time
Impulse = Final momentum - Initial momentum
The ball of mass m strikes the wall with velocity v.
So, initial momentum is= mv .....(1)
ball rebounds with same velocity but in opposite direction after striking the wall, so velocity = -v
and final momentum= -mv ......(2)
from eq. (1) and (2)
Impulse = -mv -(mv) = -2mv
and impulsive force = -2mv/ dt
Magnitude of impulsive force = 2mv/dt
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