Question:
A shell of mass 0.02 kg is fired by a given of mass 100 kg . If the speed of the shell is 80 m/s . What is the recoil speed of the gun .
Answer:
Ans. m = 0.02 kg, M = 100 kg, v = 80 m/s
Let V be the recoil speed of the gun
According to the law of conservation of momentum,
Initial momentum = Final momentum
0 = mv + MV
V = - mv/M = - 0.02 x 80/100 = - 0.016 m/s
*Negative sign indicates that the gun moves backward as the bullet moves forward.
Not what you are looking for? Go ahead and submit the question, we will get back to you.
