Question:
A bullet of mass 0.4 kg moves with a speed of 90 m/s enters a heavy wooden block and stop after a distance of 60 cm. What is the average resisitive force exerted by the block on the bullet ?
Answer:
u = 90 m/s, v = 0, S = 60 cm = 0.6m
v2 - u2 = 2as
-902 = 2 x a x 0.6
a = -902 / 2 x 0.6 = -6750 m/s2
retarding force = m a = 0.04 x 6750 = 270 N
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