Question:
A bob is suspended from a crane by a cable of length l=5m. The crane and the load are moving at a constant speed V. The crane is stopped by a bumper and the bob on the cable swings out an angle of 60(degree). Find the initial speed V. (g=9.8 m
Answer:
In this question,the cable does not work on the bob.
So,the bobs energy is conserved.
1/2 mV2 = mgh .......(1)
here, h= l cosθ = 5 cos60 = 5/2 .......(2)
from equations (1) and (2), we find
1/2 mV2 = m×9.8×5/2
V2 =49
V=7 m/sec
Not what you are looking for? Go ahead and submit the question, we will get back to you.
