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Question:
use the expressions for the fundamental frequency to show that the fundamental frequency of an open pipe is twice that of a closed pipe of the same length
Answer:

Organ pipe

The fundamental frequency of the pipe is the simplest, smallest portion of the wave that can fit into a pipe.

Open-end pipe:

At an open-end of a pipe, there is an anti node. There is an area of maximum air movement at the open end of a pipe.

For open organ pipe fundamental node, L0 = λ0 / 2 ; λ0 = 2L0 ; We know f = v/λ, Hence, f0 = v / λ0 = v / 2L0  ------Eqn (1)

Close ended pipe:

At a close ended of a pipe, there is an anti node at the open end and a node at the closed end causing sound to reflect. There is an area of maximum air movement at the open end of a pipe.

For close ended organ pipe fundamental node, L0 = λ0 / 4 ; λ0 = 4L0 ; We know f = v/λ, Hence, f0 = v / λ0 = v / 4L0 ------Eqn (2)

Comparing Eqn(1) and Eqn(2), we find , f0 of closed organ pipe = ½ times f0 of open organ pipe which means

The fundamental frequency note of open organ pipe is twice the fundamental frequency note of the closed organ pipe.

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