Question:
the volume of two bodies are measured to be v1 =10.2= -0.02 cm3 and v2 =6.4 -0.01 cm3. Calculate the sum and difference in volume with error limit.
Answer:
Volume V1 = (10.2± 0.02) cm3
and V2 =(6.4± 0.01) cm3
Sum of volumes = (10.2± 0.02) +(6.4± 0.01)
=(10.2+6.4) ± (0.02 +0.01)
=(16.6± 0.03) cm3
Difference of volumes = (10.2± 0.02) - (6.4± 0.01)
=(10.2 - 6.4) ± (0.02 +0.01)
= (3.8± 0.03) cm3
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