Question:
The circular scale of a screw gauge has 50 divisions and pitch of 0.5mm. Find the diameter of the sphere. Main scale reading is 2
Answer:
L.C (least count) = pitch/no. of divisions on circular scale
= 0.5/50
= 0.01 mm.
Diameter = MSR + LC x (VSR - 5)
2 + 0.01 x (25 - 5)
= 2.2 mm.
Not what you are looking for? Go ahead and submit the question, we will get back to you.
