

Dimension of Resistance = Potential Difference / Current = ML2T-3A-1 / A = ML2T-3A-2
Dimension of Capacitance = Charge / Potential Difference = AT/ML2T-3A-1 = M-1L-2T4A2
Dimension of self Inductance [L]=[ϕ] / [I] = MT−2L2A−1 / A = ML2T-2A-2
So answer is (a)
