Question:
If A and B are two vectors, such that A+B = A-B , then the angle between A and B.
Answer:
Given, magnitude of (A+B) = magnitude of (A-B)
|A+B| = |A-B|
(A+B)2=(A−B)2
(A+B)2−(A−B)2=0
4AB=0
AB=0
The dot product of two vectors A and B, is 0
A.B=0
Projection Theorem-
cosθ=A⋅B/|A||B|
If A⋅B=0
then cosθ=0
So,θ=π/2
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