Question:
One mole of oxygen of volume 1 litre at 4 atm pressure to attain 1 atm pressure by result of isothermal expansion. Find work done by the gas.
Answer:
Work done in isothermal expansion = W = 2.303 RT log10 (P1/P2)
R = 0.0821 Atm/mol/K
T = 298K
P1/P2 = 4/1 = 4
Also, 16.1 L = 1 Atm
Hence, W = 2.303 * 0.0821 * 298 * log10 (4) * 16.1
= 2.303 * 0.0821 * 298 * 0.6020 * 16.1 = 33.91 * 16.1 J
= 545.95 J
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