

We consider that the gas enclosed in a cubical vessel of edge L with coordinate axis.
Now,if we consider that a molecule having velocity v with components along the axes as vx , vy and vz .
The gas we take is isotropic, i.e there is no preferred direction of velocity of molecules in vessel.Therefore, by symmetry we take-
V2x = v2y =v2z = 1/3 (v2x +v2y +v2z)
Here we take mean of the velocity components in three axes (x,y,z).
So we use 1/3
