Question:
A body cools from 80 degree C to 50 degree C in 5 minutes. Calculate the time it takes to cool from 60 degree C to 30 degree C. The temperature of the surroundings is 20 degree C.
Answer:
According to Newton’s law of cooling, we have:
(-dT/T) = K(T - T0)
dT / K(T - T0) = -Kdt ....(i)
Where,
Temperature of the body = T
Temperature of the surroundings = T0 = 20°C
K is a constant
Temperature of the body falls from 80°C to 50°C in time, t = 5 min = 300 s
Integrating equation (i), we get:
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