Question:
0.1 m3 of water at 80¡ãc is mixed with 0.3m3 of water at 60¡ãc. the final temperature of mixture is-
Answer:
The water with the higher temperature will lose heat and that the water with the lower temperature will gain the same amount of heat.
Mathematically, the equation establishing the relationship between heat gained or lost and change in temperature is given by
q = m.c.ΔT
where m is the mass
c is the specific heat capacity of water
ΔT is the difference in temperature
When water at different temperature at different masses is mixed, then thermal equilibrium is reached. Let the final temperature be Tf
m1 c ΔT1 = -m2 c ΔT2
(80 – Tf) = - (0.3) (60 – Tf)
80 – Tf = - 180 + 3Tf
260 = 4Tf
Tf = 850
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