Question:
Two rings have their moment of inertia in the ratio 4:1 and their diameter are in the ratio 4:1 the ratio of their masses will be???
Answer:
As we know that , the moment of inertia for ring is-
I = MR2
Where, M is mass and R is radius of ring.
Given, I1/I2 = 4/1
I1 moment of inertia of first ring.
I2 moment of inertia of second ring.
So, I1/I2 = M1 (R1)2 /M2 (R2)2
I1/I2 = M1 (D1)2 /M2 (D2)2
D is diameter.
So, M1/M2 = (I1/I2).(D2/D1)
Therefore,
M1/M2 =(4/1).(1/4)2
M1/M2 = 1/4
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