

Mass of the Na (m1) = 23
Mass of the Cl (m2) = 36
Distance between the two atom is = d
Let, Na atom be located at X1 = 0
Let, Cl atom be located X2 = d
Let, X1 is the distance of centre of mass of the molecule from sodium atom
x = (m1 x X1 + m2 x X2)/(m1 + m2)
x = [(23 x 0) + (36 x d)]/(23 + 36)
x = [0 + 36d]/59 = 0.61 d m
