Question:
find the displacement of a simple harmonic oscillator at which its potential energy is half of the maximum energy of the oscillator
Answer:
Potential Energy = PE = ½ m ω2y2
Total Energy = T = ½ m ω2 a2
Given condition is that PE = ½ T
Hence, ½ m ω2y2 = ½ * ½ m ω2a2
which gives y2 = ½ a2
y = a/√2
Hence, the displacement should be = a/√2 for which potential energy is half of the maximum energy of the oscillator
Not what you are looking for? Go ahead and submit the question, we will get back to you.
