Question:
Displacement of a particle executing SHM is represented by Y=0.008sin(3π.t π/4)metre.Then calculate Displacement from mean position at t=7/36sec.
Answer:
The general equation of simple harmonic motion is y = A sin (ωt + ɸ)
Compare this equation with the given equation which is Y=0.008sin(3∏.t + ∏/4)metre
Hence, A = 0.008m
At t = 7/36 sec, 3∏.t = 3∏.7/36 = 21∏/36 = 7∏/36
3∏.t + ∏/4 = 7∏/36 + ∏/4 = 451/182 = 2.48
Hence, y = 0.008 * sin (2.48) = 0.00032 m
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