Question:
A particle undergoes SHM having time period T.find the time taken in 3/8th oscillation.
Answer:
If the time period of oscillation is T, then to complete 3/8 of oscillation, it will take time of 3T/8
Case 1:
However, if in the problem, time taken to complete 1 oscillation is given as 10 seconds, then the above answer will be 3 * 10 / 8 = 3.75 seconds
Case 2:
Similarly, if the problem is worded as find the displacement after 3/8 of oscillation, then we can say y = Asinωt is the SHM equation
Also, ω = 2∏/ T Hence, y = A sin (2∏/ T)(3/8T) = A sin 270 which implies y = A m
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