Question:
A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2 s. Find the acceleration and velocity of the body when the displacement is (a) 5 cm, (b) 3 cm, (c) 0 cm.
Answer:
r = 5 cm = 0.05 m
T = 0.2 s
ω = 2π/T = 2π/0.2 = 10 π rad/s
When displacement is y, then acceleration, A = -ω2 y
Case (a) When y = 5cm = 0.05 m
A = -(10π)2 × 0.05 = -5π2 m/s2
Case (b) When y = 3 cm = 0.03 m
A = -(10π)2 × 0.03 = -3π2 m/s2
Case (c) When y = 0
A = -(10π)2 × 0 = 0
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