Question:
when body falls on ground at velocity 40 m/s in 4 sec find the height
Answer:
When it is released, the stone will rise 5m before stopping.
0=100–2aD. D=5m.
Gravitational acceleration, a, is 40m/s
This will take 1 second.
10 seconds later the stone will hit the ground.
The stone will fall 500m in 10 seconds (D=1/2 aT^2)
So the release point was 5 meters below 500 meters, or 495 meters.
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