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Question:

obtain equations of motion for constant acceleration using method of calculus.

Answer:

Acceleration a is constant.

We know-

d2s /dt2 =dv/dt =a 

Integrating a with respect to time will leave us with an expression for velocity, v , (as acceleration is the rate of change of velocity, wrt time):

v=ds/dt = ∫a dt = at+u,

v= u+at  .......(1)

 

where u is a constant of integration. In context it is the initial velocity a body is travelling before it accelerates.

Integrating velocity wrt time will leave us with an expression for displacement (as velocity is the first derivative of displacement modelled as a function of time):

s =∫(ds/dt) dt = ∫(at+u) dt = ∫at dt + ∫u dt

Hence,  s= ut+(1/2)at2                           ...........(2)

Note that this equation assumes displacemnt is zero when time t= 0, i.e. the constant of integration has been neglected.

From equation (2)

s = 1/2(2u+at) t

s= 1/2(u+u+at)t  = 1/2(u+v)t                     

v2 = (u+at)2 =u2 +2uat+at2

v2 = u2 +2a(ut+1/2 at2)

= u2+2as

v2=u2+2as .............(3)

 

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